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4x^2+12x=-10
We move all terms to the left:
4x^2+12x-(-10)=0
We add all the numbers together, and all the variables
4x^2+12x+10=0
a = 4; b = 12; c = +10;
Δ = b2-4ac
Δ = 122-4·4·10
Δ = -16
Delta is less than zero, so there is no solution for the equation
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